Optimal. Leaf size=195 \[ \frac{\sqrt{d} \left (24 a^2 d^2-40 a b c d+15 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c+d x^2}}\right )}{8 b^4}+\frac{d x \sqrt{c+d x^2} (11 b c-12 a d)}{8 b^3}+\frac{(b c-6 a d) (b c-a d)^{3/2} \tan ^{-1}\left (\frac{x \sqrt{b c-a d}}{\sqrt{a} \sqrt{c+d x^2}}\right )}{2 \sqrt{a} b^4}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2} \]
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Rubi [A] time = 0.244147, antiderivative size = 195, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {467, 528, 523, 217, 206, 377, 205} \[ \frac{\sqrt{d} \left (24 a^2 d^2-40 a b c d+15 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c+d x^2}}\right )}{8 b^4}+\frac{d x \sqrt{c+d x^2} (11 b c-12 a d)}{8 b^3}+\frac{(b c-6 a d) (b c-a d)^{3/2} \tan ^{-1}\left (\frac{x \sqrt{b c-a d}}{\sqrt{a} \sqrt{c+d x^2}}\right )}{2 \sqrt{a} b^4}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2} \]
Antiderivative was successfully verified.
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Rule 467
Rule 528
Rule 523
Rule 217
Rule 206
Rule 377
Rule 205
Rubi steps
\begin{align*} \int \frac{x^2 \left (c+d x^2\right )^{5/2}}{\left (a+b x^2\right )^2} \, dx &=-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{\int \frac{\left (c+d x^2\right )^{3/2} \left (c+6 d x^2\right )}{a+b x^2} \, dx}{2 b}\\ &=\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{\int \frac{\sqrt{c+d x^2} \left (2 c (2 b c-3 a d)+2 d (11 b c-12 a d) x^2\right )}{a+b x^2} \, dx}{8 b^2}\\ &=\frac{d (11 b c-12 a d) x \sqrt{c+d x^2}}{8 b^3}+\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{\int \frac{2 c \left (4 b^2 c^2-17 a b c d+12 a^2 d^2\right )+2 d \left (15 b^2 c^2-40 a b c d+24 a^2 d^2\right ) x^2}{\left (a+b x^2\right ) \sqrt{c+d x^2}} \, dx}{16 b^3}\\ &=\frac{d (11 b c-12 a d) x \sqrt{c+d x^2}}{8 b^3}+\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{\left ((b c-6 a d) (b c-a d)^2\right ) \int \frac{1}{\left (a+b x^2\right ) \sqrt{c+d x^2}} \, dx}{2 b^4}+\frac{\left (d \left (15 b^2 c^2-40 a b c d+24 a^2 d^2\right )\right ) \int \frac{1}{\sqrt{c+d x^2}} \, dx}{8 b^4}\\ &=\frac{d (11 b c-12 a d) x \sqrt{c+d x^2}}{8 b^3}+\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{\left ((b c-6 a d) (b c-a d)^2\right ) \operatorname{Subst}\left (\int \frac{1}{a-(-b c+a d) x^2} \, dx,x,\frac{x}{\sqrt{c+d x^2}}\right )}{2 b^4}+\frac{\left (d \left (15 b^2 c^2-40 a b c d+24 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-d x^2} \, dx,x,\frac{x}{\sqrt{c+d x^2}}\right )}{8 b^4}\\ &=\frac{d (11 b c-12 a d) x \sqrt{c+d x^2}}{8 b^3}+\frac{3 d x \left (c+d x^2\right )^{3/2}}{4 b^2}-\frac{x \left (c+d x^2\right )^{5/2}}{2 b \left (a+b x^2\right )}+\frac{(b c-6 a d) (b c-a d)^{3/2} \tan ^{-1}\left (\frac{\sqrt{b c-a d} x}{\sqrt{a} \sqrt{c+d x^2}}\right )}{2 \sqrt{a} b^4}+\frac{\sqrt{d} \left (15 b^2 c^2-40 a b c d+24 a^2 d^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c+d x^2}}\right )}{8 b^4}\\ \end{align*}
Mathematica [A] time = 0.221138, size = 173, normalized size = 0.89 \[ \frac{\sqrt{d} \left (24 a^2 d^2-40 a b c d+15 b^2 c^2\right ) \log \left (\sqrt{d} \sqrt{c+d x^2}+d x\right )+b x \sqrt{c+d x^2} \left (-\frac{4 (b c-a d)^2}{a+b x^2}+d (9 b c-8 a d)+2 b d^2 x^2\right )+\frac{4 (b c-6 a d) (b c-a d)^{3/2} \tan ^{-1}\left (\frac{x \sqrt{b c-a d}}{\sqrt{a} \sqrt{c+d x^2}}\right )}{\sqrt{a}}}{8 b^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.013, size = 7459, normalized size = 38.3 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d x^{2} + c\right )}^{\frac{5}{2}} x^{2}}{{\left (b x^{2} + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 8.82906, size = 2938, normalized size = 15.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2} \left (c + d x^{2}\right )^{\frac{5}{2}}}{\left (a + b x^{2}\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.19869, size = 602, normalized size = 3.09 \begin{align*} \frac{1}{8} \, \sqrt{d x^{2} + c}{\left (\frac{2 \, d^{2} x^{2}}{b^{2}} + \frac{9 \, b^{7} c d^{3} - 8 \, a b^{6} d^{4}}{b^{9} d^{2}}\right )} x - \frac{{\left (15 \, b^{2} c^{2} \sqrt{d} - 40 \, a b c d^{\frac{3}{2}} + 24 \, a^{2} d^{\frac{5}{2}}\right )} \log \left ({\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2}\right )}{16 \, b^{4}} - \frac{{\left (b^{3} c^{3} \sqrt{d} - 8 \, a b^{2} c^{2} d^{\frac{3}{2}} + 13 \, a^{2} b c d^{\frac{5}{2}} - 6 \, a^{3} d^{\frac{7}{2}}\right )} \arctan \left (\frac{{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} b - b c + 2 \, a d}{2 \, \sqrt{a b c d - a^{2} d^{2}}}\right )}{2 \, \sqrt{a b c d - a^{2} d^{2}} b^{4}} + \frac{{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} b^{3} c^{3} \sqrt{d} - 4 \,{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} a b^{2} c^{2} d^{\frac{3}{2}} + 5 \,{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} a^{2} b c d^{\frac{5}{2}} - 2 \,{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} a^{3} d^{\frac{7}{2}} - b^{3} c^{4} \sqrt{d} + 2 \, a b^{2} c^{3} d^{\frac{3}{2}} - a^{2} b c^{2} d^{\frac{5}{2}}}{{\left ({\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{4} b - 2 \,{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} b c + 4 \,{\left (\sqrt{d} x - \sqrt{d x^{2} + c}\right )}^{2} a d + b c^{2}\right )} b^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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